### Python Code Explanation for `(n//10)%10` The expression `(n//10)%10` can be broken down into two parts: 1. **Integer Division (`n//10`)**: This operation performs integer division of `n` by 10, effectively removing the last digit from the number when represented as an integer[^1]. For example, if `n = 123`, then `n//10` results in `12`. 2. **Modulo Operation (`%10`)**: After performing the integer division, the modulo operator `%` extracts the remainder when dividing the result by 10. In this case, it isolates the second-to-last digit of the original number `n`. Continuing with the previous example where `n//10` resulted in `12`, applying `%10` yields `2` as the output. Thus, the entire expression `(n//10)%10` retrieves the tens place value (or the second-to-last digit) of any given non-negative integer `n`. #### Example Usage Below is a simple demonstration using different values of `n` to illustrate how the expression works: ```python numbers = [123, 4567, 89, 101] results = [(n, (n//10)%10) for n in numbers] print(results) ``` Output: ``` [(123, 2), (4567, 6), (89, 8), (101, 0)] ``` In each tuple within the list comprehension above, the first element represents the input number `n`, and the second element shows the corresponding result of evaluating `(n//10)%10`. ### Practical Application This type of calculation might appear frequently in algorithms involving numerical analysis or data processing tasks such as parsing digits individually out of integers, implementing certain encoding schemes like Gray codes conversion mentioned earlier[^2], etc.