在 `xml.etree.ElementTree` 中没有 `findnext` 方法，这就是出现 `AttributeError: 'xml.etree.ElementTree.Element' object has no attribute 'findnext'. Did you mean: 'findtext?'` 错误的原因。可以通过获取当前元素的父节点，然后找到当前元素在父节点中的索引，再访问下一个元素来实现类似 `findnext` 的功能。 以下是修改后的代码： ```python import xml.etree.ElementTree as ET import tkinter as tk from tkinter import filedialog # 创建一个Tkinter根窗口 root = tk.Tk() root.withdraw() # 隐藏根窗口 # 弹出文件选择对话框 file_path = filedialog.askopenfilename() if file_path: try: # 打开并读取文件 with open(file_path, 'r', encoding='utf-8') as file: content = file.read() # 输出文件路径和内容至变量 path_variable = file_path content_variable = content print(f"文件路径: {path_variable}") except Exception as e: print(f"读取文件时出现错误: {e}") else: print("未选择文件。") # 解析 XML 文件 tree = ET.fromstring(content_variable) # 查找 Attributes 下的指定键值对 attributes = tree.find('.//dict') if attributes: key_value_pairs = attributes.findall('key') for key in key_value_pairs: key_text = key.text if key_text in ['serialnumber', 'softwarename', 'softwareversion']: parent = key.getparent() index = list(parent).index(key) if index + 1 < len(parent): string_tag = parent[index + 1] if string_tag.tag == 'string': string_text = string_tag.text print(f"{key_text}: {string_text}") # 查找 Tests 数组中的测试信息 tests_array = tree.find('.//array') if tests_array: for test in tests_array.findall('dict'): test_info = {} keys = test.findall('key') for key in keys: key_text = key.text parent = key.getparent() index = list(parent).index(key) if index + 1 < len(parent): value_tag = parent[index + 1] if value_tag.tag == 'string': value_text = value_tag.text elif value_tag.tag == 'integer': value_text = int(value_tag.text) test_info[key_text] = value_text print("测试信息:", test_info) ```