兔子繁殖问题的兔子数量规律符合斐波那契数列，以下是几种 Python 实现方法： #### 方法一：使用列表存储每个月的兔子数量 ```python def fib(n): if n == 1: return [1] elif n == 2: return [1, 1] fibs = [1, 1] for i in range(n - 2): fibs.append(fibs[-1] + fibs[-2]) return fibs print(fib(5)) ``` #### 方法二：使用循环计算指定月份的兔子数量 ```python month = int(input("请输入月份： ")) if month == 1 or month == 2: print("总共有兔子数为1只") else: a = 1 b = 1 c = 0 for i in range(3, month + 1): c = a + b a = b b = c print("总共有兔子数为：", c) ``` #### 方法三：另一种循环实现 ```python # 输入第几个月 tem1, tem2, tem3 = 1, 0, 0 mountH = int(input("你要知道几月份的兔子数：")) for i in range(mountH): tem2, tem3, tem1 = tem1, tem2, tem2 + tem3 rabbit = tem1 + tem2 + tem3 print(mountH, "月有", rabbit * 2, "只兔子") ``` #### 方法四：函数返回指定月份的兔子数量列表 ```python def count_rabbits(months): if months <= 0: return 0 elif months == 1 or months == 2: return 1 rabbits = [0] * (months + 1) rabbits[1] = 1 rabbits[2] = 1 for i in range(3, months + 1): rabbits[i] = rabbits[i - 1] + rabbits[i - 2] return rabbits # 计算1 - 12个月每个月的兔子数量 all = [] rabbit_counts = count_rabbits(12) for month, count in enumerate(rabbit_counts[1:], start=1): all.append(count) print("第{}个月的兔子数量为：{}".format(month, count)) print("一年里一对种兔繁衍总数量为：{}".format(sum(all) - 1)) ```