### Python 实现石头剪刀布游戏 为了创建一个简单的石头剪刀布游戏，可以按照如下方式构建程序逻辑： ```python import random def get_user_selection(): user_choice = input("请输入您的选择 (石头, 剪刀, 布): ") if user_choice in ["石头", "剪刀", "布"]: return user_choice else: print("无效输入，请重新输入.") return get_user_selection() def get_computer_selection(): options = ["石头", "剪刀", "布"] return random.choice(options) def determine_winner(user_choice, computer_choice): outcomes = { ("石头", "剪刀"): True, ("剪刀", "布"): True, ("布", "石头"): True, ("石头", "布"): False, ("剪刀", "石头"): False, ("布", "剪刀"): False, ("石头", "石头"): None, ("剪刀", "剪刀"): None, ("布", "布"): None, } result = outcomes.get((user_choice, computer_choice)) if result is True: return "胜利" elif result is False: return "失败" else: return "平局" def play_game(): user_score = 0 computer_score = 0 for _ in range(5): print("\n--- 新的一轮 ---") user_choice = get_user_selection() computer_choice = get_computer_selection() print(f"\n您选择了 {user_choice}, 计算机选择了 {computer_choice}") outcome = determine_winner(user_choice, computer_choice) if outcome == "胜利": print("恭喜，本轮获胜!") user_score += 1 elif outcome == "失败": print("遗憾，本轮计算机胜出.") computer_score += 1 else: print("双方打成平手.") print(f"当前比分 - 用户: {user_score} | 计算机: {computer_score}") print("\n=== 游戏结束 ===") print(f"最终得分 - 用户: {user_score} | 计算机: {computer_score}") ``` 上述代码展示了如何通过定义几个辅助函数来简化主游戏循环的逻辑[^3]。