### 如何用Python编写21点游戏 #### 游戏概述 21点是一种流行的纸牌游戏，目标是在不超过21点的情况下获得尽可能高的分数。玩家可以要牌（hit），也可以停牌（stand）。当玩家或庄家超过21点，则算作爆牌并输掉这一局。 #### 准备工作 为了简化起见，在这个例子中将不考虑花色和具体数值卡牌的设计，而是直接使用整数表示每张卡片的价值[^3]。 #### 编码实现 下面是一个简单的命令行版21点游戏的Python代码： ```python import random def deal_card(): """返回一张随机的牌""" cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10] card = random.choice(cards) return card def calculate_score(cards): """计算手中牌总分，并处理A作为1还是11的情况""" if sum(cards) == 21 and len(cards) == 2: return 0 # 黑杰克 if 11 in cards and sum(cards) > 21: cards.remove(11) cards.append(1) return sum(cards) def compare(user_score, computer_score): """比较用户和电脑得分决定胜负""" if user_score == computer_score: return "平局" elif computer_score == 0: return "对方黑杰克，输了" elif user_score == 0: return "赢得比赛！" elif user_score > 21: return "超过了21点，输了" elif computer_score > 21: return "对手超过21点，赢了" elif user_score > computer_score: return "赢得了胜利" else: return "输了" def play_game(): user_cards = [] computer_cards = [] is_game_over = False for _ in range(2): # 发两张初始手牌给双方 user_cards.append(deal_card()) computer_cards.append(deal_card()) while not is_game_over: user_score = calculate_score(user_cards) computer_score = calculate_score(computer_cards) print(f"\n你的牌是{user_cards}，当前得分为 {user_score}") print(f"电脑的第一张牌是 [{computer_cards[0]}]") if user_score == 0 or computer_score == 0 or user_score > 21: is_game_over = True else: should_continue = input("按'y'继续拿牌 或者 按'n'停止: ") if should_continue.lower() == 'y': user_cards.append(deal_card()) else: is_game_over = True while computer_score != 0 and computer_score < 17: computer_cards.append(deal_card()) computer_score = calculate_score(computer_cards) print(f"\n你的最终手牌为：{user_cards}, 得分为:{user_score}") print(f"电脑的手牌为：{computer_cards}, 得分为:{computer_score}") result_message = compare(user_score, computer_score) print(result_message) if __name__ == "__main__": play_game() ``` 这段代码定义了一个基本框架来模拟21点游戏的核心逻辑，包括发牌、计分以及判断胜败等功能[^1]。