可以使用以下几种不同的方法来实现输入英文文本，将英文转为小写后统计并输出每个单词出现的次数： ### 方法一：使用自定义函数和字典 ```python import string def get_dict_word_times(text): """构建字典{单词: 次数}""" list_word_with_punctuation = text.split() # 去掉标点，不区分大小写 list_word = [word.strip(string.punctuation).lower() for word in list_word_with_punctuation] # 去掉重复单词 set_word = set(list_word) return {word: list_word.count(word) for word in set_word} # 输入英文文本 input_text = input("请输入英文文本: ") dict_word_times = get_dict_word_times(input_text) # 把单词按照次数由多到少排序 list_sorted_words = sorted(dict_word_times, key=lambda w: dict_word_times[w], reverse=True) for word in list_sorted_words: print("{} -- {} times".format(word, dict_word_times[word])) ``` ### 方法二：使用`collections.Counter` ```python import collections import string # 输入英文文本 input_text = input("请输入英文文本: ") # 去掉标点，转为小写 cleaned_text = ''.join([char for char in input_text if char not in string.punctuation]).lower() words = cleaned_text.split() word_count = collections.Counter(words) # 输出结果 for word, count in word_count.most_common(): print(f"{word} -- {count} times") ``` ### 方法三：使用字典手动统计 ```python import string # 输入英文文本 input_text = input("请输入英文文本: ") # 去掉标点，转为小写 cleaned_text = ''.join([char for char in input_text if char not in string.punctuation]).lower() words = cleaned_text.split() words_dic = {} for k in words: if k in words_dic: words_dic[k] += 1 else: words_dic[k] = 1 # 输出结果 for word, count in sorted(words_dic.items(), key=lambda item: item[1], reverse=True): print(f"{word} -- {count} times") ```