In Python 2.7, when converting the integer `1` to a hexadecimal string using the `hex()` function, the result does not include a trailing `'L'`. The output of `hex(1)` is `'0x1'`, which indicates that it is a hexadecimal representation of a regular integer[^1]. The presence of the `'L'` suffix in hexadecimal representations depends on the type of the integer being converted. In Python 2.7, integers can be of two types: regular integers (which are limited to a certain size based on the system architecture) and long integers (which support arbitrarily large values). If an integer exceeds the maximum value for a regular integer, or if it is explicitly defined as a long integer by appending `'L'` at the end of the number, its hexadecimal representation will also include the `'L'` suffix [^2]. For example: ```python hex(1) # Output: '0x1' hex(1L) # Output: '0x1L' ``` Here, `hex(1)` returns `'0x1'` because `1` is treated as a regular integer, whereas `hex(1L)` returns `'0x1L'` because `1L` is explicitly a long integer. This distinction between regular integers and long integers was removed in Python 3, where all integers behave like long integers from Python 2.7, and the `'L'` suffix is no longer used in the output of functions like `hex()` [^3]. ### Summary - For small integers, such as `1`, the `hex()` function produces a string without the `'L'` suffix. - The `'L'` suffix appears only when the input is explicitly a long integer or exceeds the range of a regular integer. - This behavior reflects the difference between regular integers and long integers in Python 2.7.