在提供的代码中，`IndentationError: expected an indented block` 错误通常是因为在需要缩进的代码块处没有正确缩进。以下是修正缩进后的代码： ```python def generate_schedule(n): if n % 2 == 0: days = n - 1 else: days = n n = n + 1 schedule = [[0] * days for _ in range(n)] def fill_schedule(start, end, days): if end - start == 1: schedule[start][0] = end schedule[end][0] = start return mid = (start + end) // 2 fill_schedule(start, mid, days // 2) fill_schedule(mid + 1, end, days // 2) for i in range(start, mid + 1): for j in range(days // 2): schedule[i][j + days // 2] = schedule[i + (end - start + 1) // 2][j] schedule[i + (end - start + 1) // 2][j + days // 2] = schedule[i][j] fill_schedule(0, n - 1, days) if n % 2 == 1: for i in range(n - 1): for j in range(days): if schedule[i][j] == n - 1: schedule[i][j] = f"队伍{i + 1} - 轮空" else: schedule[i][j] = f"队伍{i + 1} - 队伍{schedule[i][j] + 1}" else: for i in range(n): for j in range(days): schedule[i][j] = f"队伍{i + 1} - 队伍{schedule[i][j] + 1}" if n % 2 == 1: return schedule[:-1] return schedule n = int(input()) schedule = generate_schedule(n) for day in schedule: print("|".join(day)) ``` 原代码中存在以下缩进问题： 1. `fill_schedule` 函数定义后，内部代码块没有正确缩进。 2. `if n % 2 == 1:` 和 `else:` 分支下的代码块也没有正确缩进。 3. 最后返回 `scheduler` 应该是 `schedule`，属于拼写错误。