以下为你提供几种不同实现方式的Python剪刀石头布游戏代码： ### 简单函数式实现 ```python import random def get_choice(): print("请选择您要出的手势：") print("1.剪刀") print("2.石头") print("3.布") choice = input("请输入您的选择（数字）：") choices = {'1': '剪刀', '2': '石头', '3': '布'} return choices.get(choice) def get_computer_choice(): return random.choice(['剪刀', '石头', '布']) def determine_winner(player_choice, computer_choice): if player_choice == computer_choice: return "平局！" elif (player_choice == '剪刀' and computer_choice == '布') or \ (player_choice == '石头' and computer_choice == '剪刀') or \ (player_choice == '布' and computer_choice == '石头'): return "恭喜您获胜！" else: return "很遗憾，您输了！" def play_game(): player_choice = get_choice() computer_choice = get_computer_choice() winner = determine_winner(player_choice, computer_choice) print("电脑选择了：" + computer_choice) print(winner) play_again = input("是否再来一局？（是/否）") if play_again == "是": play_game() else: print("游戏结束，感谢您的参与！") play_game() ``` 此代码通过函数式编程实现了剪刀石头布游戏，包含获取玩家选择、电脑随机选择、判断胜负和控制游戏流程的功能，玩家还能选择是否继续游戏 [^1]。 ### 简化输入实现 ```python import random # 让用户输入选择，0代表石头，1代表布，2代表剪刀 player = int(input('请出拳: 石头: 0 布: 1 剪刀: 2')) # 电脑随机选择0、1或2 computer = random.randint(0, 2) # 判断游戏结果 if ((player == 0) and (computer == 2)) or ((player == 1) and (computer == 0)) or ((player == 2) and (computer == 1)): print('玩家获胜，哈哈哈') elif player == computer: print('平局，再来一次') elif player >= 3 or computer >= 3: print('没有这种出法哦') else: print('电脑获胜') # 打印电脑的选择 print('电脑出的是：', ['石头', '布', '剪刀'][computer]) ``` 该代码简化了玩家输入，使用数字代表不同手势，同时对输入范围进行了简单检查 [^2]。 ### 类实现 ```python from random import randint decision = ['石头', '剪刀', '布'] class User: def __init__(self): self.cur = None def make_decision(self): self.cur = input("请问你要出什么：") if self.cur not in decision: print("输入有误，请重新输入") return self.make_decision() return self.cur class Robot: def make_decision(self): return decision[randint(0, 2)] def determine_winner(player_choice, computer_choice): if player_choice == computer_choice: return "平局！" elif (player_choice == '剪刀' and computer_choice == '布') or \ (player_choice == '石头' and computer_choice == '剪刀') or \ (player_choice == '布' and computer_choice == '石头'): return "恭喜您获胜！" else: return "很遗憾，您输了！" def play_game(): user = User() robot = Robot() player_choice = user.make_decision() computer_choice = robot.make_decision() winner = determine_winner(player_choice, computer_choice) print("电脑选择了：" + computer_choice) print(winner) play_again = input("是否再来一局？（是/否）") if play_again == "是": play_game() else: print("游戏结束，感谢您的参与！") play_game() ``` 此代码运用类的概念，将玩家和电脑分别抽象成`User`类和`Robot`类，增强了代码的可维护性和扩展性 [^3]。