虽然提供的引用资料未提及ACM竞赛Python版模板，但可以从ACM竞赛常考的知识点来推测Python版模板可能涵盖的内容。ACM竞赛常见问题类型包括排序、动态规划、图论、字符串处理、数学、数据结构等。以下是一些常见知识点的Python版模板示例： ### 排序算法 - 快速排序 ```python def quick_sort(arr): if len(arr) <= 1: return arr else: # 选择基准值 pivot = arr[len(arr) // 2] # 分别存放比基准小和大的元素 left = [x for x in arr if x < pivot] middle = [x for x in arr if x == pivot] right = [x for x in arr if x > pivot] # 递归地对左右两边进行快排，并合并结果 return quick_sort(left) + middle + quick_sort(right) ``` ### 动态规划 - 斐波那契数列 ```python def fibonacci(n): if n <= 1: return n dp = [0] * (n + 1) dp[1] = 1 for i in range(2, n + 1): dp[i] = dp[i - 1] + dp[i - 2] return dp[n] ``` ### 图论 - 广度优先搜索（BFS） ```python from collections import deque def bfs(graph, start): visited = set() queue = deque([start]) visited.add(start) while queue: vertex = queue.popleft() print(vertex, end=" ") for neighbor in graph[vertex]: if neighbor not in visited: queue.append(neighbor) visited.add(neighbor) ``` ### 字符串处理 - KMP算法 ```python def compute_lps(pattern): m = len(pattern) lps = [0] * m length = 0 i = 1 while i < m: if pattern[i] == pattern[length]: length += 1 lps[i] = length i += 1 else: if length != 0: length = lps[length - 1] else: lps[i] = 0 i += 1 return lps def kmp(text, pattern): n = len(text) m = len(pattern) lps = compute_lps(pattern) i = 0 j = 0 while i < n: if pattern[j] == text[i]: i += 1 j += 1 if j == m: print("Pattern found at index", i - j) j = lps[j - 1] elif i < n and pattern[j] != text[i]: if j != 0: j = lps[j - 1] else: i += 1 ``` ### 数据结构 - 栈 ```python class Stack: def __init__(self): self.items = [] def is_empty(self): return len(self.items) == 0 def push(self, item): self.items.append(item) def pop(self): if not self.is_empty(): return self.items.pop() return None def peek(self): if not self.is_empty(): return self.items[-1] return None def size(self): return len(self.items) ```