以下是一个使用 Python 编写的简化版 2048 游戏，基于命令行界面。该游戏实现了基本的移动和合并逻辑，可以使用方向键（W/A/S/D）进行操作。 ```python import random import os import sys def initialize_board(size=4): """初始化一个size x size的游戏板，初始时有两个随机位置为2""" board = [[0 for _ in range(size)] for _ in range(size)] add_new_tile(board) add_new_tile(board) return board def add_new_tile(board): """在游戏板上随机选择一个空位放置2或4（90%概率为2）""" empty_cells = [(i, j) for i in range(len(board)) for j in range(len(board[0])) if board[i][j] == 0] if not empty_cells: return i, j = random.choice(empty_cells) board[i][j] = random.choice([2, 2, 2, 2, 4]) # 90% 概率为2 def print_board(board): """打印当前游戏板状态""" os.system('cls' if os.name == 'nt' else 'clear') print("2048 Game (Use W/A/S/D to move. Press Q to quit.)") for row in board: print("+------" * len(row) + "+") print("|" + "|".join(f"{num:^6}" if num != 0 else " " for num in row) + "|") print("+------" * len(board[0]) + "+") def compress(row): """将非零元素左移，填补空白""" new_row = [i for i in row if i != 0] new_row += [0] * (len(row) - len(new_row)) return new_row def merge(row): """合并相邻相同的数字（从左到右合并）""" for i in range(len(row) - 1): if row[i] != 0 and row[i] == row[i + 1]: row[i] *= 2 row[i + 1] = 0 return row def move_left(board): """执行一次向左移动操作""" moved = False new_board = [] for row in board: compressed = compress(row) merged = merge(compressed) final = compress(merged) new_board.append(final) if row != final: moved = True return new_board, moved def rotate_clockwise(board): """顺时针旋转矩阵90度""" return [list(row) for row in zip(*board[::-1])] def move_right(board): """向右移动：先翻转每一行，再向左移动，最后再翻转回来""" reversed_board = [row[::-1] for row in board] new_board, moved = move_left(reversed_board) return [row[::-1] for row in new_board], moved def move_up(board): """向上移动：将矩阵顺时针旋转三次，然后向左移动，最后恢复""" rotated = rotate_clockwise(board) rotated = rotate_clockwise(board) rotated = rotate_clockwise(board) new_rotated, moved = move_left(rotated) restored = rotate_clockwise(new_rotated) return restored, moved def move_down(board): """向下移动：将矩阵顺时针旋转一次，然后向左移动，最后恢复""" rotated = rotate_clockwise(board) new_rotated, moved = move_left(rotated) restored = rotate_clockwise(new_rotated) restored = rotate_clockwise(restored) restored = rotate_clockwise(restored) return restored, moved def check_game_over(board): """检查是否没有可移动的空间，即游戏结束""" for i in range(len(board)): for j in range(len(board[0])): if board[i][j] == 0: return False if j < len(board[0]) - 1 and board[i][j] == board[i][j + 1]: return False if i < len(board) - 1 and board[i][j] == board[i + 1][j]: return False return True def main(): board = initialize_board() while True: print_board(board) if check_game_over(board): print("Game Over!") break move = input("Enter move (W/A/S/D): ").lower() if move == 'q': print("Thanks for playing!") break elif move == 'w': board, moved = move_up(board) elif move == 'a': board, moved = move_left(board) elif move == 's': board, moved = move_down(board) elif move == 'd': board, moved = move_right(board) else: print("Invalid input! Use W/A/S/D or Q.") continue if moved: add_new_tile(board) if __name__ == "__main__": main() ``` ### 解释： - `initialize_board`：初始化一个 4x4 的棋盘，并随机放置两个 2。 - `add_new_tile`：在空白格子中随机添加一个新的 2 或 4（2 的概率更高）。 - `print_board`：打印当前棋盘状态。 - `compress` 和 `merge`：实现一行数据的压缩与合并逻辑。 - `move_left/right/up/down`：实现四个方向的移动逻辑。 - `rotate_clockwise`：用于辅助实现上下左右移动的旋转功能。 - `check_game_over`：判断是否已经无法移动，即游戏结束。 - `main`：主函数，处理用户输入、更新棋盘并检测游戏是否结束。 ---